Integrand size = 15, antiderivative size = 64 \[ \int x^2 \cot ^2(a+i \log (x)) \, dx=-6 e^{2 i a} x-\frac {x^3}{3}-\frac {2 e^{2 i a} x^3}{e^{2 i a}-x^2}+6 e^{3 i a} \text {arctanh}\left (e^{-i a} x\right ) \]
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Time = 0.10 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {4592, 456, 474, 470, 327, 213} \[ \int x^2 \cot ^2(a+i \log (x)) \, dx=6 e^{3 i a} \text {arctanh}\left (e^{-i a} x\right )-\frac {2 e^{2 i a} x^3}{-x^2+e^{2 i a}}-6 e^{2 i a} x-\frac {x^3}{3} \]
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Rule 213
Rule 327
Rule 456
Rule 470
Rule 474
Rule 4592
Rubi steps \begin{align*} \text {integral}& = \int \frac {\left (-i-\frac {i e^{2 i a}}{x^2}\right )^2 x^2}{\left (1-\frac {e^{2 i a}}{x^2}\right )^2} \, dx \\ & = \int \frac {x^2 \left (-i e^{2 i a}-i x^2\right )^2}{\left (-e^{2 i a}+x^2\right )^2} \, dx \\ & = -\frac {2 e^{2 i a} x^3}{e^{2 i a}-x^2}+\frac {1}{2} e^{-2 i a} \int \frac {x^2 \left (-10 e^{4 i a}-2 e^{2 i a} x^2\right )}{-e^{2 i a}+x^2} \, dx \\ & = -\frac {x^3}{3}-\frac {2 e^{2 i a} x^3}{e^{2 i a}-x^2}-\left (6 e^{2 i a}\right ) \int \frac {x^2}{-e^{2 i a}+x^2} \, dx \\ & = -6 e^{2 i a} x-\frac {x^3}{3}-\frac {2 e^{2 i a} x^3}{e^{2 i a}-x^2}-\left (6 e^{4 i a}\right ) \int \frac {1}{-e^{2 i a}+x^2} \, dx \\ & = -6 e^{2 i a} x-\frac {x^3}{3}-\frac {2 e^{2 i a} x^3}{e^{2 i a}-x^2}+6 e^{3 i a} \text {arctanh}\left (e^{-i a} x\right ) \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.56 \[ \int x^2 \cot ^2(a+i \log (x)) \, dx=-\frac {x^3}{3}-4 x \cos (2 a)+6 \text {arctanh}(x (\cos (a)-i \sin (a))) \cos (3 a)-4 i x \sin (2 a)+\frac {2 x (\cos (3 a)+i \sin (3 a))}{\left (-1+x^2\right ) \cos (a)-i \left (1+x^2\right ) \sin (a)}+6 i \text {arctanh}(x (\cos (a)-i \sin (a))) \sin (3 a) \]
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Time = 1.07 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.75
method | result | size |
risch | \(-\frac {7 x^{3}}{3}-\frac {2 x^{3}}{\frac {{\mathrm e}^{2 i a}}{x^{2}}-1}-6 \,{\mathrm e}^{2 i a} x +6 \,\operatorname {arctanh}\left (x \,{\mathrm e}^{-i a}\right ) {\mathrm e}^{3 i a}\) | \(48\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 102 vs. \(2 (47) = 94\).
Time = 0.24 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.59 \[ \int x^2 \cot ^2(a+i \log (x)) \, dx=-\frac {x^{5} + 11 \, x^{3} e^{\left (2 i \, a\right )} - 9 \, {\left (x^{2} - e^{\left (2 i \, a\right )}\right )} e^{\left (3 i \, a\right )} \log \left ({\left (x e^{\left (2 i \, a\right )} + e^{\left (3 i \, a\right )}\right )} e^{\left (-2 i \, a\right )}\right ) + 9 \, {\left (x^{2} - e^{\left (2 i \, a\right )}\right )} e^{\left (3 i \, a\right )} \log \left ({\left (x e^{\left (2 i \, a\right )} - e^{\left (3 i \, a\right )}\right )} e^{\left (-2 i \, a\right )}\right ) - 18 \, x e^{\left (4 i \, a\right )}}{3 \, {\left (x^{2} - e^{\left (2 i \, a\right )}\right )}} \]
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Time = 0.18 (sec) , antiderivative size = 60, normalized size of antiderivative = 0.94 \[ \int x^2 \cot ^2(a+i \log (x)) \, dx=- \frac {x^{3}}{3} - 4 x e^{2 i a} + \frac {2 x e^{4 i a}}{x^{2} - e^{2 i a}} - 3 \left (\log {\left (x - e^{i a} \right )} - \log {\left (x + e^{i a} \right )}\right ) e^{3 i a} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 335 vs. \(2 (47) = 94\).
Time = 0.22 (sec) , antiderivative size = 335, normalized size of antiderivative = 5.23 \[ \int x^2 \cot ^2(a+i \log (x)) \, dx=-\frac {2 \, x^{5} + 22 \, x^{3} {\left (\cos \left (2 \, a\right ) + i \, \sin \left (2 \, a\right )\right )} + 18 \, {\left ({\left (-i \, \cos \left (3 \, a\right ) + \sin \left (3 \, a\right )\right )} \arctan \left (\sin \left (a\right ), x + \cos \left (a\right )\right ) + {\left (-i \, \cos \left (3 \, a\right ) + \sin \left (3 \, a\right )\right )} \arctan \left (\sin \left (a\right ), x - \cos \left (a\right )\right )\right )} x^{2} - 36 \, x {\left (\cos \left (4 \, a\right ) + i \, \sin \left (4 \, a\right )\right )} + 18 \, {\left ({\left (i \, \cos \left (2 \, a\right ) - \sin \left (2 \, a\right )\right )} \cos \left (3 \, a\right ) - {\left (\cos \left (2 \, a\right ) + i \, \sin \left (2 \, a\right )\right )} \sin \left (3 \, a\right )\right )} \arctan \left (\sin \left (a\right ), x + \cos \left (a\right )\right ) + 18 \, {\left ({\left (i \, \cos \left (2 \, a\right ) - \sin \left (2 \, a\right )\right )} \cos \left (3 \, a\right ) - {\left (\cos \left (2 \, a\right ) + i \, \sin \left (2 \, a\right )\right )} \sin \left (3 \, a\right )\right )} \arctan \left (\sin \left (a\right ), x - \cos \left (a\right )\right ) - 9 \, {\left (x^{2} {\left (\cos \left (3 \, a\right ) + i \, \sin \left (3 \, a\right )\right )} - {\left (\cos \left (2 \, a\right ) + i \, \sin \left (2 \, a\right )\right )} \cos \left (3 \, a\right ) - {\left (i \, \cos \left (2 \, a\right ) - \sin \left (2 \, a\right )\right )} \sin \left (3 \, a\right )\right )} \log \left (x^{2} + 2 \, x \cos \left (a\right ) + \cos \left (a\right )^{2} + \sin \left (a\right )^{2}\right ) + 9 \, {\left (x^{2} {\left (\cos \left (3 \, a\right ) + i \, \sin \left (3 \, a\right )\right )} - {\left (\cos \left (2 \, a\right ) + i \, \sin \left (2 \, a\right )\right )} \cos \left (3 \, a\right ) + {\left (-i \, \cos \left (2 \, a\right ) + \sin \left (2 \, a\right )\right )} \sin \left (3 \, a\right )\right )} \log \left (x^{2} - 2 \, x \cos \left (a\right ) + \cos \left (a\right )^{2} + \sin \left (a\right )^{2}\right )}{6 \, {\left (x^{2} - \cos \left (2 \, a\right ) - i \, \sin \left (2 \, a\right )\right )}} \]
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Time = 0.31 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.30 \[ \int x^2 \cot ^2(a+i \log (x)) \, dx=-\frac {x^{5}}{3 \, {\left (x^{2} - e^{\left (2 i \, a\right )}\right )}} - \frac {11 \, x^{3} e^{\left (2 i \, a\right )}}{3 \, {\left (x^{2} - e^{\left (2 i \, a\right )}\right )}} - \frac {6 \, \arctan \left (\frac {x}{\sqrt {-e^{\left (2 i \, a\right )}}}\right ) e^{\left (4 i \, a\right )}}{\sqrt {-e^{\left (2 i \, a\right )}}} + \frac {10 \, x e^{\left (4 i \, a\right )}}{x^{2} - e^{\left (2 i \, a\right )}} \]
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Time = 27.40 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.89 \[ \int x^2 \cot ^2(a+i \log (x)) \, dx=-{\left ({\mathrm {e}}^{a\,2{}\mathrm {i}}\right )}^{3/2}\,\mathrm {atan}\left (\frac {x\,1{}\mathrm {i}}{\sqrt {{\mathrm {e}}^{a\,2{}\mathrm {i}}}}\right )\,6{}\mathrm {i}-\frac {x^3}{3}-4\,x\,{\mathrm {e}}^{a\,2{}\mathrm {i}}-\frac {2\,x\,{\mathrm {e}}^{a\,4{}\mathrm {i}}}{{\mathrm {e}}^{a\,2{}\mathrm {i}}-x^2} \]
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